Q. I=2V/R+2 r
A. I = (2V/R) + 2r
I - (2V/R) = 2r
r = (1/2) * [I - (2V/R)]
r = (I/2) - (V/R)
But if you meant to write I = 2V / (R+2r),
I * (R + 2r) = 2V
IR + 2rI = 2V
2rI = 2V - IR
r = (2V - IR) / 2I
r = (V/I) - (R/2)
How do you solve this for r....?
Q. 2k+ar=r-3y
A. â°Answerâ°
r = (-3y - 2k)/(a - 1)
âDerivationâ
2k + ar = r - 3y
Try different ways to find the value of r. Isolating r variables is the better way to solve for r.
ar = r - 3y - 2k
ar - r = -3y - 2k
Factor the left side.
r(a - 1) = -3y - 2k
r = (-3y - 2k)/(a - 1)
Determine the r-values?
Q. Let V and S denote the volume and total surface area, respectively, of a right circular cylinder of radius r and height 1 unit. For which r-values will the ratio V/S be less than 1/3?
A. (Ïr^2h)/(2Ïrh+2Ïr^2)<1/3
(Ïr^2)/(2Ïr+2Ïr^2)<1/3
(Ïr^2)/2Ïr(1+r)<1/3
r/2(1+r)<1/3
r<1/3(2+2r)
r<2/3+2r/3
r-2r/3<2/3
r(1-2/3)<2/3
r<(2/3)/(1-2/3)
r<6/3
r<2
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Title : Math formulas solve for r?
Description : Q. I=2V/R+2 r A. I = (2V/R) + 2r I - (2V/R) = 2r r = (1/2) * [I - (2V/R)] r = (I/2) - (V/R) But if you meant to write I = 2V / (R+2r), I...