Q. 10.5 = R*12^2 / (1.49 + R)^2
r />A. 10.5 = R*12^2 / (1.49 + R)^2
Simplify:
10.5=R*144/(1.49+R)^2
Expand:
10.5=R*144/1.49^2+R^2
Simplify again:
10.5=R*144/2.2201+R^2
10.5=R*64.862+R^2
Therefore:
10.5/64.862=R*R^2
0.162=R^3
cube root(0.162)=R
0.545=R
Math formulas solve for r?
Q. I=2V/R+2r
A. I = (2V/R) + 2r
I - (2V/R) = 2r
r = (1/2) * [I - (2V/R)]
r = (I/2) - (V/R)
But if you meant to write I = 2V / (R+2r),
I * (R + 2r) = 2V
IR + 2rI = 2V
2rI = 2V - IR
r = (2V - IR) / 2I
r = (V/I) - (R/2)
How do you solve this for r....?
Q. 2k+ar=r-3y
A. â°Answerâ°
r = (-3y - 2k)/(a - 1)
âDerivationâ
2k + ar = r - 3y
Try different ways to find the value of r. Isolating r variables is the better way to solve for r.
ar = r - 3y - 2k
ar - r = -3y - 2k
Factor the left side.
r(a - 1) = -3y - 2k
r = (-3y - 2k)/(a - 1)
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Title : Could someone solve this equation for R?
Description : Q. 10.5 = R*12^2 / (1.49 + R)^2 r /> A. 10.5 = R*12^2 / (1.49 + R)^2 Simplify: 10.5=R*144/(1.49+R)^2 Expand: 10.5=R*144/1.49^2+R^2 Sim...